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A cube of any crystal has A-atoms placed at every corner and B-atoms placed at every centre of face. The formula of compound :
A
AB
B
$AB_3$
C
$A_2B_2$
D
$A_2B_3$
Detailed Solution
A atoms at 8 corners: $8 \times \dfrac{1}{8} = 1$
B atoms at 6 face centres: $6 \times \dfrac{1}{2} = 3$
Ratio A : B = 1 : 3
So the formula is $AB_3$.
B atoms at 6 face centres: $6 \times \dfrac{1}{2} = 3$
Ratio A : B = 1 : 3
So the formula is $AB_3$.
