The number of octahedral void(s) per atom present in a cubic close-packed structure is

1 2012 AIPMT-PRE The Solid StateVoids in close packing Easy
The number of octahedral void(s) per atom present in a cubic close-packed structure is
A 4
B 1
C 3
D 2

Detailed Solution

A ccp (fcc) unit cell has 4 atoms.
Octahedral voids: 1 at the body centre + 12 edge centres × $\frac{1}{4}$ = 4
Octahedral voids per atom $= \frac{4}{4} = 1$

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