Considering entropy (S) as a thermodynamic parameter, the criterion for the spontaneity of any process is :-
A
$\Delta S_{system} - \Delta S_{surroundings} \gt 0$
B
$\Delta S_{system} \gt 0$ only
C
$\Delta S_{surroundings} \gt 0$ only
D
$\Delta S_{system} + \Delta S_{surroundings} \gt 0$
The answer is D.
Solution
According to the second law of thermodynamics, a process is spontaneous if the total entropy of the universe increases. $\Delta S_{total} = \Delta S_{universe} = \Delta S_{system} + \Delta S_{surroundings}$ For a spontaneous process: $\Delta S_{system} + \Delta S_{surroundings} \gt 0$. At equilibrium $\Delta S_{total} = 0$. Entropy of the system alone or of the surroundings alone is not enough; for example, freezing of water below $0^\circ C$ is spontaneous although $\Delta S_{system}$ is negative, because $\Delta S_{surroundings}$ is larger and positive. So the criterion is $\Delta S_{system} + \Delta S_{surroundings} \gt 0$.
ConceptSecond law criterion of spontaneity
Entropy and Spontaneity in past papers
2 questions from this chapter have appeared across 2 exam years.