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Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is: [Given that $1\ L\ bar=100\ J$]
A
$-30\ J$
B
$5\ kJ$
C
$25\ J$
D
$30\ J$
Detailed Solution
For irreversible expansion against a constant external pressure: $W_{irr}=-P_{ext}\Delta V$
$W=-2\ bar\times(0.25-0.1)\ L=-2\times0.15\ L\,bar=-0.30\ L\,bar$
$W=-0.30\times100\ J=-30\ J$