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For very high frequencies, the effective impedance of the circuit (shown in the figure, with a mix of resistors, inductors of 2mH & 1mH, capacitors of 2$\mu F$ & 1$\mu F$) will be:- [add image]
A
4 $\Omega$
B
6 $\Omega$
C
1 $\Omega$
D
3 $\Omega$
Detailed Solution
At very high frequencies, capacitors behave like short circuits ($X_C\approx0$) and inductors behave like open circuits ($X_L\to\infty$). Simplifying the given circuit under this limit, the effective circuit reduces to two resistors (1 $\Omega$ and 2 $\Omega$) in series, giving an effective impedance of $3\ \Omega$.