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An ac voltage is applied to a resistance R and inductor L in series. If R and the inductive reactance are both equal to 3 $\Omega$, the phase difference between the applied voltage and the current in the circuit is
A
Zero
B
$\pi/6$
C
$\pi/4$
D
$\pi/2$
Detailed Solution
In a series LR circuit the voltage leads the current by an angle $\phi$ given by $\tan\phi = \frac{X_L}{R}$
$\tan\phi = \frac{3}{3} = 1$
$\phi = 45^\circ$
$\phi = \frac{\pi}{4}$
$\tan\phi = \frac{3}{3} = 1$
$\phi = 45^\circ$
$\phi = \frac{\pi}{4}$