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When an electron does transition from n = 4 to n = 2, then emitted line in spectrum will be :
A
First line of Lyman series
B
Second line of Balmer series
C
First line of Paschen series
D
Second line of Paschen series
Detailed Solution
Transitions ending at n = 2 belong to the Balmer series (visible region).
First line of Balmer series: n = 3 $\rightarrow$ 2 ($H_\alpha$). Second line: n = 4 $\rightarrow$ 2 ($H_\beta$).
So the transition n = 4 to n = 2 gives the second line of the Balmer series.
First line of Balmer series: n = 3 $\rightarrow$ 2 ($H_\alpha$). Second line: n = 4 $\rightarrow$ 2 ($H_\beta$).
So the transition n = 4 to n = 2 gives the second line of the Balmer series.