The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of 10…

The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of 10 $\Omega$ is
A 1.0 $\Omega$
B 0.2 $\Omega$
C 0.5 $\Omega$
D 0.8 $\Omega$

Detailed Solution


$I = \frac{E}{r + R} \Rightarrow 0.2 = \frac{2.1}{r + 10}$
$r = 0.5\ \Omega$

Cells and internal resistance in past papers

2 questions from this chapter have appeared across 2 exam years.

Keep going

Practise Cells and internal resistance All 2 questions This chapter in 2013 NEET