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The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of 10 $\Omega$ is
A
1.0 $\Omega$
B
0.2 $\Omega$
C
0.5 $\Omega$
D
0.8 $\Omega$
Detailed Solution
$I = \frac{E}{r + R} \Rightarrow 0.2 = \frac{2.1}{r + 10}$
$r = 0.5\ \Omega$
