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A carbon resistor of $(47 \pm 4.7)\ k\Omega$ is to be marked with rings of different colours for its identification. The colour code sequence will be
Explanation
Digits 4, 7 = yellow, violet; ×10³ = orange; ±10% = silver.
Detailed Solution
$(47 \pm 4.7)\ k\Omega = 47 \times 10^{3}\ \Omega \pm 10\%$
4 → Yellow, 7 → Violet, multiplier $10^3$ → Orange, tolerance 10% → Silver
$\therefore$ Colour code: Yellow – Violet – Orange – Silver