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Two cities are 150 km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8 volt and the average resistance per km is 0.5 $\Omega$. The power loss in the wire is:
A
19.2 W
B
19.2 kW
C
19.2 J
D
12.2 kW
Detailed Solution
Resistance = (0.5 $\Omega$/km)(150 km) = 75 $\Omega$
Total voltage drop = (8 V/km)(150 km) = 1200 V
Power loss $= \frac{(\Delta V)^2}{R} = \frac{(1200)^2}{75} = 19200$ W = 19.2 kW
Total voltage drop = (8 V/km)(150 km) = 1200 V
Power loss $= \frac{(\Delta V)^2}{R} = \frac{(1200)^2}{75} = 19200$ W = 19.2 kW