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A car battery of emf 12 V and internal resistance $5 \times 10^{-2}\ \Omega$ receives a current of 60 A from external source, then terminal voltage of battery is :
A
12 V
B
9 V
C
15 V
D
20 V
Detailed Solution
The battery is receiving current from an external source, i.e. it is being charged. During charging, the terminal voltage is greater than the emf:
$V = E + Ir$
$V = 12 + 60 \times 5 \times 10^{-2} = 12 + 3$
$V = 15$ V
$V = E + Ir$
$V = 12 + 60 \times 5 \times 10^{-2} = 12 + 3$
$V = 15$ V