Looking for classes? Ksquare Career Institute, Bengaluru →
The threshold frequency of a photoelectric metal is $\nu_0$. If light of frequency $4\nu_0$ is incident on this metal, then the maximum kinetic energy of emitted electrons will be
Detailed Solution
$h\nu=h\nu_0+KE_{max} \Rightarrow h(4\nu_0)=h\nu_0+KE_{max} \Rightarrow KE_{max}=3h\nu_0$.