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By photoelectric effect, Einstein proved :
A
$E = h\nu$
B
$KE = \dfrac{1}{2}mv^2$
C
$E = mc^2$
D
$E = \dfrac{-Rhc}{n^2}$
Detailed Solution
Einstein explained the photoelectric effect by assuming that light consists of quanta (photons), each with energy $E = h\nu$.
A photon gives all its energy to one electron: $h\nu = \phi + KE_{max}$.
This explained why the electron energy depends on frequency and why there is a threshold frequency, which the wave theory could not explain.
So by the photoelectric effect, Einstein established $E = h\nu$ (the quantum nature of light).
A photon gives all its energy to one electron: $h\nu = \phi + KE_{max}$.
This explained why the electron energy depends on frequency and why there is a threshold frequency, which the wave theory could not explain.
So by the photoelectric effect, Einstein established $E = h\nu$ (the quantum nature of light).