Looking for classes? Ksquare Career Institute, Bengaluru →
An electromagnetic wave of wavelength $\lambda$ is incident on a photosensitive surface of negligible work function. If $m$ mass is of photoelectron emitted from the surface has de-Broglie wavelength $\lambda_d$, then:
A
$\lambda_d=\left(\frac{2mc}{h}\right)\lambda^2$
B
$\lambda=\left(\frac{2mc}{h}\right)\lambda_d^2$
C
$\lambda=\left(\frac{2h}{mc}\right)\lambda_d^2$
D
$\lambda=\left(\frac{2m}{hc}\right)\lambda_d^2$
Detailed Solution
Work function is negligible: $\frac{hc}{\lambda} = K_{max}$
$\lambda_d = \frac{h}{\sqrt{2mK_{max}}} \Rightarrow K_{max} = \frac{h^2}{2m\lambda_d^2}$
$\frac{hc}{\lambda} = \frac{h^2}{2m\lambda_d^2} \Rightarrow \lambda = \left(\frac{2mc}{h}\right)\lambda_d^2$