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According to Gauss law of electrostatics, electric flux through a closed surface depends on:
A
the area of the surface
B
the quantity of charges enclosed by the surface
C
the shape of the surface
D
the volume enclosed by the surface
Detailed Solution
By Gauss's law, $\phi=\dfrac{q_{inside}}{\varepsilon_0}$, which depends only on the charge enclosed by the surface, not its area, shape, or enclosed volume.
