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A square loop of side 1 m and resistance $1\ \Omega$ is placed in a magnetic field of 0.5 T. If the plane of loop is perpendicular to the direction of the magnetic field, the magnetic flux through the loop is :
A
zero weber
B
2 weber
C
0.5 weber
D
1 weber
Detailed Solution
The plane of the loop is perpendicular to B, so the area vector is parallel to B (angle = 0).
$\phi = BA\cos 0^\circ = 0.5 \times (1)^2 \times 1 = 0.5$ Wb