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A cycle wheel of radius 0.5 m is rotated with constant angular velocity of 10 rad/s in a region of magnetic field of 0.1 T which is perpendicular to the plane of the wheel. The EMF generated between its centre and the rim is,
Detailed Solution
$E=\frac{1}{2}B\omega l^2=\frac{1}{2}\times0.1\times10\times(0.5)^2=0.125$ V.
