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Two coils of self inductances 2 mH and 8 mH are placed so close together that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils is :
A
10 mH
B
6 mH
C
4 mH
D
16 mH
Detailed Solution
Mutual inductance of two coils: $M = K\sqrt{L_1 L_2}$, where $K$ is the coefficient of coupling.
The flux of one coil is completely linked with the other, so the coupling is perfect: $K = 1$.
Here $L_1 = 2$ mH and $L_2 = 8$ mH.
$M = \sqrt{2 \times 8} = \sqrt{16}$
$M = 4$ mH
The flux of one coil is completely linked with the other, so the coupling is perfect: $K = 1$.
Here $L_1 = 2$ mH and $L_2 = 8$ mH.
$M = \sqrt{2 \times 8} = \sqrt{16}$
$M = 4$ mH