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A capacitor of capacitance $C$, is connected across an ac source of voltage $V$, given by $V=V_0\sin\omega t$. The displacement current between the plates of the capacitor, would then be given by:
A
$I_d=\frac{V_0}{\omega C}\cos\omega t$
B
$I_d=\frac{V_0}{\omega C}\sin\omega t$
C
$I_d=V_0\omega C\sin\omega t$
D
$I_d=V_0\omega C\cos\omega t$
