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If $\lambda_v$, $\lambda_x$ and $\lambda_m$ represent the wavelengths of visible light, x-rays and microwaves respectively, then -
A
$\lambda_m \gt \lambda_x \gt \lambda_v$
B
$\lambda_v \gt \lambda_m \gt \lambda_x$
C
$\lambda_v \gt \lambda_x \gt \lambda_m$
D
$\lambda_m \gt \lambda_v \gt \lambda_x$
Detailed Solution
The electromagnetic spectrum in decreasing order of wavelength is: radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, gamma rays.
Microwaves have wavelengths of about 1 mm to 0.3 m.
Visible light has wavelengths of about 400 nm to 700 nm.
X-rays have wavelengths of about $10^{-8}$ m to $10^{-13}$ m.
So $\lambda_m \gt \lambda_v \gt \lambda_x$
Microwaves have wavelengths of about 1 mm to 0.3 m.
Visible light has wavelengths of about 400 nm to 700 nm.
X-rays have wavelengths of about $10^{-8}$ m to $10^{-13}$ m.
So $\lambda_m \gt \lambda_v \gt \lambda_x$