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In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0\times10^{10}\ Hz$ and amplitude $48\ Vm^{-1}$. Then the amplitude of oscillating magnetic field is: (Speed of light in free space $=3\times10^8\ ms^{-1}$)
A
$1.6\times10^{-6}\ T$
B
$1.6\times10^{-9}\ T$
C
$1.6\times10^{-8}\ T$
D
$1.6\times10^{-7}\ T$
Explanation
$B_0=\frac{E_0}{c}=1.6\times10^{-7}\ T$.
Detailed Solution
$B=\frac{E}{C}=\frac{48}{3\times10^8}=16\times10^{-8}=1.6\times10^{-7}\ T$