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$\varepsilon_0$ and $\mu_0$ are the electric permittivity and magnetic permeability of free space respectively. If the corresponding quantities of a medium are $2\varepsilon_0$ and $1.5\mu_0$ respectively, the refractive index of the medium will nearly be:
A
$\sqrt2$
B
$\sqrt3$
C
3
D
2
Detailed Solution
$\mu=\dfrac{C}{v}=\dfrac{1/\sqrt{\mu_0\varepsilon_0}}{1/\sqrt{1.5\mu_0\times2\varepsilon_0}}=\sqrt{1.5\times2}=\sqrt3$.