The capacitance of a parallel plate capacitor with air as medium is $6\ \mu F$. With the introduction of a dielectric medium, the capacitance becomes $30\ \mu F$. The permittivity of the medium is: ($\epsilon_0=8.85\times10^{-12}\ C^2N^{-1}m^{-2}$)

A $1.77\times10^{-12}\ C^2N^{-1}m^{-2}$

B $0.44\times10^{-10}\ C^2N^{-1}m^{-2}$

C $5.00\ C^2N^{-1}m^{-2}$

D $0.44\times10^{-13}\ C^2N^{-1}m^{-2}$

The answer is B.

Solution

$C = KC_0 \Rightarrow K = \frac{C}{C_0} = \frac{30}{6} = 5$ $K = \frac{\epsilon}{\epsilon_0} \Rightarrow \epsilon = K\epsilon_0 = 5 \times 8.85 \times 10^{-12}$ $\epsilon = 0.44 \times 10^{-10}\ C^2N^{-1}m^{-2}$

Concept permittivity from capacitance ratio

Electrostatic Potential and Capacitance in past papers

76 questions from this chapter have appeared across 27 exam years.

The capacitance of a parallel plate capacitor with air as medium is $6\ \mu F$. With the introduction of a dielectric medium, the capacitance becomes $30\ \mu F$. The permittivity of the medium is: ($\epsilon_0=8.85\times10^{-12}\ C^2N^{-1}m^{-2}$)

Solution

Electrostatic Potential and Capacitance in past papers

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