Looking for classes? Ksquare Career Institute, Bengaluru →
The distance between the two plates of a parallel plate capacitor is doubled and the area of each plate is halved. If C is its initial capacitance, its final capacitance is equal to:
Detailed Solution
$C=\frac{A\varepsilon_0}{d}$. New capacitance $C'=\frac{(A/2)\varepsilon_0}{2d}=\frac{C}{4}$.