Looking for classes? Ksquare Career Institute, Bengaluru →
A spherical planet has a mass $M_p$ and diameter $D_p$. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
A
$\frac{4GM_pm}{D_p^2}$
B
$\frac{4GM_p}{D_p^2}$
C
$\frac{GM_pm}{D_p^2}$
D
$\frac{GM_p}{D_p^2}$
Detailed Solution
$g = \frac{GM_p}{R^2}$, and $R = \frac{D_p}{2}$
$g = \frac{GM_p}{(D_p/2)^2} = \frac{4GM_p}{D_p^2}$
It does not depend on the mass m of the particle.
$g = \frac{GM_p}{(D_p/2)^2} = \frac{4GM_p}{D_p^2}$
It does not depend on the mass m of the particle.