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Dependence of intensity of gravitational field (E) of earth with distance (r) from centre of earth is correctly represented by:
A
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B
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C
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D
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Detailed Solution
Inside the earth ($r < R$) the field grows linearly with distance: $E = \frac{GMr}{R^3} \propto r$.
Outside ($r > R$) it falls off as $E = \frac{GM}{r^2} \propto \frac{1}{r^2}$.
So E rises as a straight line from zero at the centre to a maximum at r = R and then decreases as $\frac{1}{r^2}$.
Outside ($r > R$) it falls off as $E = \frac{GM}{r^2} \propto \frac{1}{r^2}$.
So E rises as a straight line from zero at the centre to a maximum at r = R and then decreases as $\frac{1}{r^2}$.
