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The time period of a geostationary satellite is 24 h, at a height $6R_E$ ($R_E$ is radius of earth) from surface of earth. The time period of another satellite whose height is $2.5R_E$ from surface will be,
Detailed Solution
$\frac{T_2}{T_1}=\left(\frac{r_2}{r_1}\right)^{3/2}=\left(\frac{3.5R}{7R}\right)^{3/2}=\frac{1}{2\sqrt{2}} \Rightarrow T_2=\frac{24}{2\sqrt{2}}=6\sqrt{2}$ h.