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The mean free path of molecules of a gas, (radius 'r') is inversely proportional to:
A
$r^3$
B
$r^2$
C
r
D
$\sqrt r$
Detailed Solution
Mean free path $\lambda_m = \frac{1}{\sqrt2\,\pi d^2n}$, where d = diameter of the molecule
So $\lambda_m \propto \frac{1}{r^2}$
So $\lambda_m \propto \frac{1}{r^2}$