Looking for classes? Ksquare Career Institute, Bengaluru →
A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If the banking angle is $45^\circ$, the speed of the car is
A
10 $ms^{-1}$
B
20 $ms^{-1}$
C
30 $ms^{-1}$
D
5 $ms^{-1}$
Detailed Solution
On a frictionless banked road: $\tan\theta = \frac{v^2}{rg}$
$v = \sqrt{rg\tan\theta} = \sqrt{90\times10\times\tan45^\circ}$
$v = \sqrt{900} = 30$ m/s
$v = \sqrt{rg\tan\theta} = \sqrt{90\times10\times\tan45^\circ}$
$v = \sqrt{900} = 30$ m/s