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A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is
A
Zero
B
MV
C
1.5 MV
D
2 MV
Detailed Solution
Impulse = change in momentum = final momentum − initial momentum.
Take the direction of rebound as positive. Initial momentum = −MV (towards the wall).
Final momentum = +MV (away from the wall, same speed).
Impulse = MV − (−MV) = 2MV
So the magnitude of the impulse experienced by the body is 2 MV.
Take the direction of rebound as positive. Initial momentum = −MV (towards the wall).
Final momentum = +MV (away from the wall, same speed).
Impulse = MV − (−MV) = 2MV
So the magnitude of the impulse experienced by the body is 2 MV.