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A particle is moving such that its position coordinates (x, y) are (2 m, 3 m) at time t = 0, (6 m, 7 m) at time t = 2 s and (13 m, 14 m) at time t = 5 s. Average velocity vector $(\vec V_{av})$ from t = 0 to t = 5 s is:
A
$\frac{1}{5}(13\hat i + 14\hat j)$
B
$\frac{7}{3}(\hat i + \hat j)$
C
$2(\hat i + \hat j)$
D
$\frac{11}{5}(\hat i + \hat j)$
Detailed Solution
$\vec v_{av} = \frac{\Delta\vec r}{\Delta t} = \frac{(13-2)\hat i + (14-3)\hat j}{5 - 0} = \frac{11}{5}(\hat i + \hat j)$