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A car runs at a constant speed on a circular track of radius 100 m, taking 62.8 seconds for every circular lap. The average velocity and average speed for each circular lap respectively is :
A
0, 0
B
0, 10 m/s
C
10 m/s, 10 m/s
D
10 m/s, 0
Detailed Solution
After one complete lap the car returns to its starting point, so the displacement is zero.
Average velocity $= \dfrac{\text{Displacement}}{\text{Time taken}} = \dfrac{0}{62.8} = 0$
Distance covered in one lap $= 2\pi r$
Average speed $= \dfrac{\text{Distance}}{\text{Time taken}} = \dfrac{2\pi r}{T} = \dfrac{(2\pi)(100)}{62.8}$
$= \dfrac{628}{62.8} = 10$ m s$^{-1}$
So the average velocity is 0 and the average speed is 10 m/s.
Average velocity $= \dfrac{\text{Displacement}}{\text{Time taken}} = \dfrac{0}{62.8} = 0$
Distance covered in one lap $= 2\pi r$
Average speed $= \dfrac{\text{Distance}}{\text{Time taken}} = \dfrac{2\pi r}{T} = \dfrac{(2\pi)(100)}{62.8}$
$= \dfrac{628}{62.8} = 10$ m s$^{-1}$
So the average velocity is 0 and the average speed is 10 m/s.