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A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time $t_1$ if the elevator is at rest and in time $t_2$ if the elevator is moving uniformly. Then:
Detailed Solution
A uniformly moving elevator is an inertial frame, so in both cases the coin falls freely relative to the floor: $t_1=t_2=\sqrt{\frac{2h}{g}}$.