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Two toroids 1 and 2 have total number of turns 200 and 100 respectively with average radii 40 cm and 20 cm respectively. If they carry same current i, the ratio of the magnetic fields along the two loops is:
Detailed Solution
$B=\frac{\mu_0Ni}{2\pi r}$. $\frac{B_1}{B_2}=\frac{N_1}{N_2}\times\frac{r_2}{r_1}=\frac{200}{100}\times\frac{20}{40}=1:1$.