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The magnetic field on the axis of a circular loop of radius 100 cm carrying current $I=\sqrt{2}$ A, at point 1 m away from the centre of the loop is given by:
Detailed Solution
$B=\frac{\mu_0 I R^2}{2(R^2+x^2)^{3/2}}=\frac{4\pi\times10^{-7}\times\sqrt{2}\times1^2}{2(1^2+1^2)^{3/2}}=\frac{4\pi\times10^{-7}\times\sqrt{2}}{2\times2\sqrt{2}}=\pi\times10^{-7}\approx3.14\times10^{-7}$ T.