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Two identical bar magnets are fixed with their centres at a distance d apart. A stationary charge Q is placed at P in between the gap of the two magnets at a distance D from the centre O as shown in the figure.
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The force on the charge Q is
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The force on the charge Q is
A
Zero
B
Directed along OP
C
Directed along PO
D
Directed perpendicular to the plane of paper
Detailed Solution
Magnetic force on a charge: $\vec{F} = Q(\vec{v}\times\vec{B})$
The charge is stationary, so v = 0.
$F = QvB\sin\theta = 0$, whatever the magnetic field at P due to the two magnets may be.
A magnetic field exerts a force only on a moving charge; a steady magnet produces no electric field to act on a charge at rest.
Hence the force on the charge Q is zero.
The charge is stationary, so v = 0.
$F = QvB\sin\theta = 0$, whatever the magnetic field at P due to the two magnets may be.
A magnetic field exerts a force only on a moving charge; a steady magnet produces no electric field to act on a charge at rest.
Hence the force on the charge Q is zero.