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The rate of radioactive disintegration at an instant for a radioactive sample of half life $2.2\times10^9$ s is $10^{10}$ s$^{-1}$. The number of radioactive atoms in that sample at that instant is,
Detailed Solution
$R=\lambda N \Rightarrow N=\frac{R\,t_{1/2}}{0.693}=\frac{10^{10}\times2.2\times10^9}{0.693}=3.17\times10^{19}$ atoms.