Consider the following nuclear reaction: $^{238}U\rightarrow\ ^{234}Th+\ ^{4}He$ Take masses of $^{238}U$, $^{234}Th$ and $^{4}He$ as 238.050 u, 234.043 u and 4.003 u, respectively. The Q value for the reaction, in keV, is: [Given: 1 u = 931.5 MeV c$^{-2}$]