2003 AIPMT OscillationsSpring-Mass System Medium Question 4 of 4 in Spring-Mass System

The time period of a mass suspended from a spring is T. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be -

A $\dfrac{T}{4}$
B T
C $\dfrac{T}{2}$
D 2T

The answer is C.

Solution

For a spring, the spring constant is inversely proportional to its length: $kl$ = constant.
Each quarter has length $\dfrac{l}{4}$, so its spring constant is $k' = 4k$.
Time period: $T = 2\pi\sqrt{\dfrac{m}{k}}$
$T' = 2\pi\sqrt{\dfrac{m}{4k}} = \dfrac{1}{2} \times 2\pi\sqrt{\dfrac{m}{k}} = \dfrac{T}{2}$
So the new time period is $\dfrac{T}{2}$.

Concept Spring constant inversely proportional to length

Spring-Mass System in past papers

4 questions from this chapter have appeared across 4 exam years.