Which one of the following statements is true for the speed 'v' and the acceleration 'a' of a particle executing simple harmonic motion

For SHM $x = A\sin\omega t$:
Velocity: $v = \omega\sqrt{A^2 - x^2}$
Acceleration: $a = -\omega^2 x$
At the mean position ($x = 0$): $v = v_{max} = A\omega$ and $a = 0$.
At the extreme positions ($x = \pm A$): $v = 0$ and $a = a_{max} = \omega^2 A$.
So in SHM, if $v = v_{max}$ then $a = 0$, and if $v = 0$ then $a = a_{max}$.
The true statement is: when 'v' is maximum, a is zero.