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An ideal Zener diode with breakdown voltage of -3 V is reverse biased with a negative input voltage $V_i=-5$ V. The magnitude of voltage difference between point B and A is:
Detailed Solution
The Zener diode is reverse biased beyond breakdown, so the voltage drop across it is 3 V. The voltage difference across B and A (the resistor) is $V_{BA}=5-3=2$ V.