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A wheel has angular acceleration of 3.0 rad/sec$^2$ and an initial angular speed of 2.00 rad/sec. In a time of 2 sec it has rotated through an angle (in radian) of
A
10
B
12
C
4
D
6
Detailed Solution
For uniform angular acceleration: $\theta = \omega_0 t + \dfrac{1}{2}\alpha t^2$
Here $\alpha$ is the angular acceleration and $\omega_0$ is the initial angular speed.
$\omega_0 = 2$ rad/s, $\alpha = 3$ rad/s$^2$, $t = 2$ s
$\theta = 2 \times 2 + \dfrac{1}{2} \times 3 \times (2)^2$
$\theta = 4 + 6$
$\theta = 10$ rad
Here $\alpha$ is the angular acceleration and $\omega_0$ is the initial angular speed.
$\omega_0 = 2$ rad/s, $\alpha = 3$ rad/s$^2$, $t = 2$ s
$\theta = 2 \times 2 + \dfrac{1}{2} \times 3 \times (2)^2$
$\theta = 4 + 6$
$\theta = 10$ rad