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Number of atoms per unit cell in B.C.C. : -
A
9
B
4
C
2
D
1
Detailed Solution
In a body-centred cubic (BCC) unit cell, there is one atom at each of the 8 corners and one atom at the body centre.
Each corner atom is shared by 8 unit cells: contribution $= 8 \times \dfrac{1}{8} = 1$
The body-centre atom belongs entirely to the cell: contribution $= 1$
Total $= 1 + 1 = 2$ atoms per unit cell.
(Simple cubic has 1 and FCC has 4.)
Each corner atom is shared by 8 unit cells: contribution $= 8 \times \dfrac{1}{8} = 1$
The body-centre atom belongs entirely to the cell: contribution $= 1$
Total $= 1 + 1 = 2$ atoms per unit cell.
(Simple cubic has 1 and FCC has 4.)
