Solution

Heat current through a conductor of area $A$ and length $l$: $\frac{dH}{dt}=KA\frac{\Delta T}{l}$ $K=\frac{l}{A\,\Delta T}\frac{dH}{dt}$ Unit of $K=\frac{m\cdot W}{m^2\cdot K}=W\,m^{-1}K^{-1}$

Concept unit of thermal conductivity

Thermal Properties of Matter in past papers

49 questions from this chapter have appeared across 25 exam years.