Looking for classes? Ksquare Career Institute, Bengaluru →
The two ends of a metal rod are maintained at temperatures $100^\circ C$ and $110^\circ C$. The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures $200^\circ C$ and $210^\circ C$, the rate of heat flow will be
A
44.0 J/s
B
16.8 J/s
C
8.0 J/s
D
4.0 J/s
Detailed Solution
Rate of heat conduction: $\frac{dQ}{dt} = \frac{KA(T_2 - T_1)}{L} \propto (T_2 - T_1)$
The temperature difference is $10^\circ C$ in both cases.
So the rate of heat flow remains 4.0 J/s.
The temperature difference is $10^\circ C$ in both cases.
So the rate of heat flow remains 4.0 J/s.