Looking for classes? Ksquare Career Institute, Bengaluru →
A black body has wavelength $\lambda_m$ corresponding to maximum energy at 2000 K. Its wavelength corresponding to maximum energy at 3000 K will be : -
A
$\dfrac{3}{2}\lambda_m$
B
$\dfrac{2}{3}\lambda_m$
C
$\dfrac{16}{81}\lambda_m$
D
$\dfrac{81}{16}\lambda_m$
Detailed Solution
Wien's displacement law: $\lambda_m T$ = constant
$\lambda_m \times 2000 = \lambda_m' \times 3000$
$\lambda_m' = \dfrac{2000}{3000}\lambda_m = \dfrac{2}{3}\lambda_m$
The peak shifts to a shorter wavelength at the higher temperature.
$\lambda_m \times 2000 = \lambda_m' \times 3000$
$\lambda_m' = \dfrac{2000}{3000}\lambda_m = \dfrac{2}{3}\lambda_m$
The peak shifts to a shorter wavelength at the higher temperature.