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In an adiabatic expansion, the temperature of one mole of an ideal monatomic gas ($\gamma=5/3$) decreases from 60 K to 50 K. The work done by the gas in the process is: (Take the universal gas constant as R = 8.3 J mol$^{-1}$ K$^{-1}$)
Detailed Solution
$W=\frac{\mu R\Delta T}{1-\gamma}=\frac{1\times8.3\times(-10)}{1-\frac{5}{3}}=\frac{3\times8.3\times10}{2}=124.5$ J.
