A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is:

A 0.25 mm

B 0.5 mm

C 1.0 mm

D 0.01 mm

The answer is B.

Solution

Least count $= \frac{pitch}{number\ of\ divisions\ on\ circular\ scale}$ $0.01\ mm = \frac{pitch}{50}$ Pitch = 0.5 mm

Concept pitch from least count

2 questions from this chapter have appeared across 2 exam years.