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Two slits in Young's double slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is $600\times10^{-9}$ m then the fringe separation is
Detailed Solution
Fringe width $\beta=\dfrac{\lambda D}{d}=\dfrac{600\times10^{-9}\times1}{1.5\times10^{-3}}=4\times10^{-4}$ m.
