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Two cars moving in opposite directions approach each other with speed of 22 m/s and 16.5 m/s respectively. The driver of the first car blows a horn having a frequency 400 Hz. The frequency heard by the driver of the second car is [velocity of sound 340 m/s]
Explanation
Source and observer approach each other, so the apparent frequency increases.
Detailed Solution
$f_A = f\left[\frac{v + v_o}{v - v_s}\right]$
$= 400\left[\frac{340 + 16.5}{340 - 22}\right]$
$f_A = 448$ Hz
